Question

sa se afle media aricmetica a numerelor a,b,c,d stiind ca a supra 2 = b supra 4 = c supra 5 =d supra 6 iar media aricmetica a numerelor a,b,c este 22​

Answer 1

Răspuns:

Vezi rezolvarea mai jos:

Explicație pas cu pas:

ma = (a + b + c + d) : 4

$\frac{a}{2} = \frac{b}{4} = \frac{c}{5} = \frac{d}{6} = k\\\frac{a}{2} = k -> a = 2k\\\frac{b}{4} = k -> b = 4k\\\frac{c}{5} = k -> c = 5k\\\frac{d}{6} = k -> d = 6k\\ma = (a + b + c) : 3 = 22\\22 = (2k+ 4k + 5k) : 3\\22 = 11k : 3\\11k = 22 * 3\\11k = 66\\k = 66 : 11\\k = 6\\a = 2k = 2 * 6 = 12\\b = 4k = 4 * 6 = 24\\c = 5k = 5 * 6 = 30\\d = 6k = 6 * 6 = 36\\ma = (a + b + c + d) : 4\\ma = (12 + 24 + 30 + 36) : 4\\ma = 102 : 4\\ma = 25.5$