Question

Sa se afle n in : 3 x 8+1-{14-[51-5 x (13-n x 2)-22]:4}=12

Answer 1

Răspuns: $\bf \red{ \underline{n = 4}}$

Explicație pas cu pas:

$\bf 3 \cdot 8+1- \{14-[51-5\cdot (13-n\cdot 2)-22]:4 \}=12$

$\bf 24+1- \{14-[51-5\cdot (13-n\cdot 2)-22]:4 \}=12$

$\bf 25- \{14-[51-5\cdot (13-n\cdot 2)-22]:4 \}=12$

$\bf 25 = 12 + \{14-[51-5\cdot (13-n\cdot 2)-22]:4 \}$

$\bf 25 - 12 = \{14-[51-5\cdot (13-n\cdot 2)-22]:4 \}$

$\bf 13 = \{14-[51-5\cdot (13-n\cdot 2)-22]:4 \}$

$\bf 13 = 14-[51-5\cdot (13-n\cdot 2)-22]:4 \: \: \: \: \: \bigg| \cdot 4$

$\bf 52= 56-[51-5\cdot (13-n\cdot 2)-22]$

$\bf 52 +[51-5\cdot (13-n\cdot 2)-22] = 56$

$\bf [51-5\cdot (13-n\cdot 2)-22] = 56 - 52$

$\bf 51-5\cdot (13-n\cdot 2)-22 = 4$

$\bf 51-5\cdot (13-n\cdot 2) = 4 + 22$

$\bf 51-5\cdot (13-n\cdot 2) = 26$

$\bf 51 = 26 + 5\cdot (13-n\cdot 2)$

$\bf 51 - 26 = 5\cdot (13-n\cdot 2)$

$\bf 25= 5\cdot (13-n\cdot 2) \: \: \: \: \: \bigg|: 5$

$\bf 5= 13-n\cdot 2$

$\bf 5 + n\cdot 2 = 13$

$\bf n\cdot 2 = 13 - 5$

$\bf n\cdot 2 = 8$

$\bf n = 8 : 2$

$\bf \red{ \underline{n = 4}}$

==pav38==

Baftă multă !