Question

sa se afle NEN si cifrele a si b stiind ca 1ab ori n+2ab+ab=11ab

Answer 1

1ab ori n+2ab+ab=11ab
(100+ab)·n+(200+ab)+ab=1100+ab
100n+ab·n+200+ab+ab=1100+ab
100n+ab(n+1)=900
ab=(900-100n)/(n+1)
ab=100(9-n)/(n+1)
ab=100[10-(n+1)]/(n+1)
ab=100·[10/(n+1)-1]
(n+1) divizor al lui 10⇒(n+1)∈{1,2,5,10}⇒n∈{0,1,4,9}
n=0⇒ab=900(Fals)
n=1⇒ab=400(Fals)
n=4⇒ab=100(Fals)
n=9⇒ab=0(Fals)