Question

Sa se afle nr x,y,z stiind ca x si y direct proportionale cu 2 si 4 si media aritmetica 12,iar z este media geometrica a nr x si y

Answer 1

x/2=y/4=>x=y/2
(x+y)/2=12=>
(x+y)=6
y/2+y=6
y+2y=12
3y=12=> y=12/3=4=>
x=4/2=2
z=√x*y=√2*4=2*√2