Question

sa se afle numerele a,b si c daca sunt invers proportionale cu 2, 3 si 5 iar suma lor este 620

Answer 1

a/1/2=b/1/3=c/1/5=k
a/1/2=k
a=k/2
b=k/3
c=k/5
a+b+c=620
k/2+k/3+k/5=620(aducem la acelasi numitor-numitor comun 30)
15k+10k+6k/30=620
31k/30=620
31k=620/30
31k=18 600
k=600
a=600/2
a=300
b=600/3
b=200
c=600/5
c=120