Question

Sa se afle numerele de forma xyz in baza 10 stiind ca xy+yz+zx=121 si x<y<z

Answer 1

Răspuns:

10 x + y + 10 y+ z + 10 z + x = 121

11 x+ 11 y + 11 z = 121

11 × ( x + y + z) = 121

x + y + z = 121:11

x + y + z = 11 si x < y < z

1 + 2 + 8 = 11 ; 1 + 3 + 7 = 11 ; 1 + 4 + 6 = 11;  2 + 3 + 6 = 11;  2  + 4 + 5 = 11

Deci numerele de forma xyz in baza 10 stiind ca xy + yz + zx = 121 si x<y<z sunt :  128, 137, 146, 236, 245