Question

sa se afle numerele naturale a,b,c,d siind ca sunt indeplinite simultan conditiile:a+b+c+d=320 b+c+d=284 c+d=192 si d=2a+b:20
urgent va rog

Answer 1

Răspuns

a+b+c+d=320

b+c+d=284

c+d=192

d=2a+b:20

a+284=320=>a=320-284=>a=36

b+192=284=>b=284-192=>b=92

d=2·36+92:20=>d=72+4,6=>d=76,6

c+76,6=192=>c=192-76,6=>c=115,4