Question

sa se afle numererele nr. naturale a si b,stiind ca suma lor este 79,iar daca impartim nr. mai mare la cel mic obtinem catul 2 si restul 19.

Answer 1

$a+b=79 \\\\ a:b=2 \ rest \ 19 \\\\ a=2*b+19 \\\\\\ 2b+19+b=79 \\\\ 3b=79-19 \\\\ 3b=60 \ \ \ |:3 \\\\ \boxed{b=20} \\\\ a=2*20+19 \\\\ a=40+19 \\\\ \boxed{a=59}$

Answer 2

a+b=79
a:b=2 rest 19

a=2xb+19
inlocuim:
2b+19+b=79
3b=79-19
3b=60
b=60:3
b=20
a=2x20+19=
a=40+19
a=59