Question

sa se afle perechile de nr naturale a si b, astfel incat: 11-{40-6×[17-(2×a×b:3-2):2+5]:4}:2=6​

Answer 1

Răspuns:

Explicație pas cu pas:

11-{40-6×[17-(2×a×b÷3-2)÷2+5]÷4}÷2=6

{40-6×[17-(2×a×b÷3-2)÷2+5]÷4}÷2=11-6

{40-6×[17-(2×a×b÷3-2)÷2+5]÷4}÷2=5

40-6×[17-(2×a×b÷3-2)÷2+5]÷4=5×2

40-6×[17-(2×a×b÷3-2)÷2+5]÷4=10

6×[17-(2×a×b÷3-2)÷2+5]÷4=40-10

6×[17-(2×a×b÷3-2)÷2+5]÷4=30

6×[17-(2×a×b÷3-2)÷2+5]=30×4

6×[17-(2×a×b÷3-2)÷2+5]=120

17-(2×a×b÷3-2)÷2+5=120÷6

17-(2×a×b÷3-2)÷2+5=20

17-(2×a×b÷3-2)÷2=20-5

17-(2×a×b÷3-2)÷2=15

(2×a×b÷3-2)÷2=17-15

(2×a×b÷3-2)÷2=2

2×a×b÷3-2=2×2

2×a×b÷3-2=4

2×a×b÷3=4+2

2×a×b÷3=6

2×a×b=6×3

2×a×b=18

a×b=18÷2

a×b=9

a=1

b=9

a=3

b=3

a=9

b=1