Question

sa se afle suma a trei numere pare consecutive a b c a<b<c stiind ca a+c=84.

Answer 1

a /---/
b /---/+2
c /---/+4
a+c=84
84-4=80
80/2=40
a=40
c=40+4
c=44
b=40+2
b=42
40+42+44=126
suma=126