Question

Sa se afle suma numerelor a+b+c , stiind ca:
a-b=477
a:b=12rest 15
bx5=cx3

Answer 1

a:b=12r15
a=12b+15
a-b=477
12b+15-b=477
11b=462
b=42
a=477+42=519
bx5=cx3
42x5=3c
3c=210
c=210:3
c=70
a+b+c=519+42+70=631

Answer 2

a + b + c = ?
a - b = 477
a : b = 12 rest 15  ⇒ a = 12b + 15
12b + 5 - b = 477
11b = 477 - 15
11b = 462
b = 462 : 11
b = 42
a = 12 * 42 + 15
a = 519
5 * 42 = 3c
c = 210 : 3
c = 70
a + b + c = 519 + 42 + 70 = 631