Question

sa se afle termenul al saptelea in dezvoltarea binomului (3y+x)^14

Answer 1

$T_{6+1}= C^6_{14}*(3y)^8*x^6= \frac{14!}{6!!8!} *3^8y^8x^6= \frac{9*10*11*12*13*14}{1*2*3*4*5*6} *6561x^6y^8 \\ =19702683x^6y^8$