Question

sa se afle trei numere stiind ca mediile aritmetice a doua cate doua numere sunt : 2,(3); 3,(1), respectiv 1(5)

Answer 1

$\frac{x+y}{2} =2,(3)=\frac{21}{9} =\frac{7}{3}$
(x+y)·3=2·7
x+y=$\frac{14}{3}$
$\frac{x+z}{2} =3,(1)=\frac{28}{9}$
x+z=$\frac{56}{9}$
$\frac{y+z}{2}=1,(5)= \frac{14}{9} }$
y+z=$\frac{28}{9}$
x+y+x+z+y+z=$\frac{42+56+28}{9}$
2(x+y+z)=$\frac{126}{9}$
2(x+y+z)=14
x+y+z=7
x=7-(y+z)=7-$\frac{28}{9}$=$\frac{63-28}{9}$=$\frac{35}{9}$
y=7-(x+z)=$\frac{63-56}{9}$=$\frac{7}{9}$
z=7-(x+y)=$\frac{21-14}{3}$=$\frac{7}{3}$