Question

SA se afle x din :
A) (8+3x)* 14-30= 1792
B) {[(3x+5)*3+]*3+5}*3+5=281  :P    C)1+{2*[3+(x-4)*5]:6}*7=8
D)9*[9*(x:9-222)+1]+1=100   :P


OFER CEL MAI INTELIGENT RASPUNS ,PLZZ

Answer 1

A) (8+3x)* 14-30= 1792
(8+3x)* 14= 1792+30
112+42x= 1822
42x=1822-112
42x=1710
x=1710/42
x=285/7
x=40,(714285)

B) {[(3x+5)*3+5]*3+5}*3+5=281
{[(3x+5)*3+5]*3+5}*3=281-5 
{[(3x+5)*3+5]*3+5}*3=276
[(3x+5)*3+5]*3+5=92 
[(3x+5)*3+5]*3=92 -5
[(3x+5)*3+5]*3=87
(3x+5)*3=29-5
(3x+5)*3=24
3x+5=8
3x=3
x=1


C)1+{2*[3+(x-4)*5]:6}*7=8
{2*[3+(x-4)*5]:6}*7=8-1
{2*[3+(x-4)*5]:6}*7=7
2*[3+(x-4)*5]:6=1
2*[3+(x-4)*5]=6
3+(x-4)*5=3
(x-4)*5=3-3
(x-4)*5=0
x-4=0
x=4

D)9*[9*(x:9-222)+1]+1=100 
9*[9*(x:9-222)+1]=100 -1
9*[9*(x:9-222)+1]=99
9*(x:9-222)+1=11
9*(x:9-222)=10
x-1998=10
x=10+1998
x=2008