Question

sa se afle x din relatiile: a)1+2·{3²+7·[5⁴-4·(x-3·5⁴)]}+1993⁰=1994 b)25·[13·72:(1+23:x)-36]-37=38

Answer 1

a) 1+2×{9+7×[625-4×(x-3×625)]}+1=1994
1+2×{9+7×[625-4×(x-1875)]}=1994-1
1+2×{9+7×[625-4×(x-1875)]}=1993
2×{9+7×[625-4×(x-1875 )]}=1993-1
2×{9+7×[625-4×(x-1875)]}=1992
9+7×[625-4×(x-1875)]=1992÷2
9+7×[625-4×(x-1875)]=996
7×[625-4×(x-1875)]=996-9
7×[625-4×(x-1875)]=987
625-4×(x-1875)=987÷7
625-4×(x-1875)= 141
4×(x-1875)=625-141
4×(x-1875)=484
x-1875=484÷4
x-1875=121
x=1875+121
x=1996


b) 25×[13×72÷(1+23:x)-36]-37=38
25×[936:(1+23:x)-36]-37=38
25×[936:(1+23:x)-36]=38+37
25×[936:(1+23:x)-36]=75
936:(1+23:x)-36=75:25
936:(1+23:x)-36=3
936:(1+23:x)=36+3
936:(1+23:x)=39
1+23:x=936:39
1+23:x=24
23:x=24-1
23:x=23
x=23:23
x=1

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