Question

sa se afle x din relatiile:a) 1+2×{3la puterea 2+ 7×[5la puterea 4 -4×(x-3×5 la puterea 4)]}+1993 la puterea 0==1994

Answer 1

a) 1+2×{3²+ 7×[5⁴ -4×(x-3×5⁴)]}+1993⁰=1994
1+2×{9+ 7×[625 -4×(x-1875)]}+1=1994
2×{9+ 7×[625 -4×(x-1875)]}=1994-1-1
2×{9+ 7×[625 -4×(x-1875)]}=1992
9+ 7×[625 -4×(x-1875)]=1992:2
9+ 7×[625 -4×(x-1875)]=996
7×[625 -4×(x-1875)]=996-9
7×[625 -4×(x-1875)]=987
625 -4×(x-1875)=987:7
625 -4×(x-1875)=141
625-141=4×(x-1875)
4×(x-1875)=484
x-1875=484:4
x-1875=121
x=121+1875
x=1996