Question

Sa se afle x,y,z daca sunt invers proportionale cu 2, 3, 4 iar suma lor este 13
DAU COROANA ESTE URGENT

Answer 1

[tex]2x=3y=4z, |:12 ; \frac{x}{6} = \frac{y}4}= \frac{z}{3}=k ; x=6k,y=4k,z=3k;[/tex] $x+y+z=13k=13; k=1,;x=6,y=4,z=3$

Answer 2

x/(1/2)=k x=k/2
y/(1/3)=k y=k/3
z/(1/4)=k z=k/4
x+y+z=13
k/2+k/3+k/4=13
6k+4k+3k=156
13k=156
k=12
x=k/2=12/2=6
y=k/3=12/3=4
z=k/4=12/4=3

Pls coroana de aur Bafta!