Question

sa se arate ca log in baza 3 din 24=1+3a.........a=log in baza 3 din 2

Answer 1

[tex]a= log_{3}2 [/tex]

$3a=3* log_{3}2=log_{3}2^3= log_{3}8$

$1+3a=1+ log_{3}8= log_{3}3+ log_{3}8= log_{3}(8*3)=log _{3}24$

Answer 2

Să reformulăm :

$\it a = log_3 2 \Longrightarrow log_324=1+3a.$

R:

$\it log_3 24 =log_3 3\cdot8= log_3 3 +log_38 =1+log_32^3=1 +3log_32 =$

$\it= 1+3a.$

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