Question

sa se arate ca log4 16 +log3 9 +$\sqrt[3]{27}$ este natural

Answer 1

$\displaystyle log_416+log_39+ \sqrt[3]{27} =log_44^2+log_33^2+ \sqrt[3]{3^3} = \\ =2log_44+2log_33+3=2+2+3=4+3=7 \in N$