Question

sa se calculeze.....

Answer 1

$\sqrt[3]{9} - \frac{3}{ \sqrt[3]{3} } = \frac{ \sqrt[3]{27}-3 }{ \sqrt[3]{3} } = \frac{9-3}{\sqrt[3]{3}} = \frac{6}{\sqrt[3]{3}} = \frac{6\sqrt[3]{3}}{3} =2\sqrt[3]{3}$