Question

Sa se calculeze:
2log₃ 5 - 10 log₃ 1+ log₃ 1 supra 400

Answer 1

log in 3 din 5² -0+ log in 3 din 1/4*100²=
=log in 3 din 25*1/4*25*4*100=
=log in 3 din 1/16*100=
=1/2 log in 3 din 1/40

Cu bine!

Answer 2

$log_{3}5^2-0+ log_{3} 400^{-1}= log_{3}25- log_{3}400= log_{3} \frac{25}{400}= log_{3} \frac{1}{16}$