Question

sa se calculeze 5/3 la-1-radical de ordin 3 din125+log√2

Answer 1

$( \frac{5}{3})^{-1}- \sqrt[3]{125}+log_2 \sqrt{2}= \frac{1}{ \frac{5}{3}}- \sqrt[3]{5^3}+ log_2 2^{\frac{1}{2}}= \frac{3}{5}-5+ \frac{1}{2}log_22=\\=\frac{3}{5}-5+ \frac{1}{2}= \frac{6-50+5}{10}=\frac{-39}{10}$