Question

Să se calculeze |-|a|+1| unde a este : a) -6 ; b) 4 ; c) - radical 7 ; d) -4/3 ; e) radical 8 - 3 . Rezolvati exercitiul dat ​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Explicație pas cu pas:

a)

a = - 6 => |a| = |-6| = 6

$|-|a| + 1| = |-6 + 1| = |-5| = 5$

b)

a = 4 => |a| = |4| = 4

$|-|a| + 1| = |-4 + 1| = |-3| = 3$

c)

$a = - \sqrt{7} \implies |a| = | - \sqrt{7} | = \sqrt{7}$

$| - |a| + 1| = | - \sqrt{7} + 1| = |1 - \sqrt{7} | = - (1 - \sqrt{7}) = \sqrt{7} - 1$

d)

$a = - \frac{4}{3} \implies |a| = \Big| - \frac{4}{3} \Big| = \frac{4}{3}$

$\Big | - |a| + 1 \Big| = \Big | - \frac{4}{3} + 1 \Big| = \Big | - \frac{1}{3}\Big| = \frac{1}{3}$

e)

$a = \sqrt{8} - 3 < 0 \implies |a| = | \sqrt{8} - 3| = 3 - \sqrt{8}$

$\Big | - |a| + 1 \Big| = \Big | - (3 - \sqrt{8}) + 1 \Big| = \Big | - 3 + \sqrt{8} + 1 \Big| = \Big | \sqrt{8} - 2\Big| = \sqrt{8} - 2$