Question

Sa se calculeze.
a) (2a+b+3)la a2a
b) (a-b+2c)la a2a
c) (x la a3a-x+2) la a2a
d) (3+2b)la a3a

Answer 1

a)(2a+b+3)la2=(4a)la2+(b)la2+9
b)=(a)la2+(b)la2+4c(la2)
c)(x)la6-(x) la2+4
d)27+(8b)la2

Answer 2

1) (2a+b+3)² = 2a²+b²+3²+2*2a*b+2*b*3+2*2a*3 = 4a²+b²+9+4ab+6b+12a
2) (a-b+2c)² = a²+b²+2c²-2ab+2a*2c-2b*2c =a²+b²+c²-2ab+4ac-4bc
4) (x³-x+2)² = x⁶+x²+2²-2x³*x+2*x³*2-2*x*2 = x⁶+x²+4-2x⁴+4x³-4x
5) (3+2b)³ = 3³+3*3²*2b+3*3*(2b)²+(2b)³ = 27+54b+36b²+8b³