Question

sa se calculeze:
a)3+2x [(2²⁷x3³⁵)²:(2⁵¹x3⁶⁹)-4¹⁷:2³³+35]=
b)3³+3²⁰:3¹⁸x3+3x3⁸:3⁶+3¹⁰:(8x3⁵+3⁵)-4x3³=

Answer 1

a)3+2*[(2²⁷*3³⁵)²:(2⁵¹*3⁶⁹)-4¹⁷:2³³+35]=
   3+2*{[(2²⁷)²*(3³⁵)²]:(2⁵¹*3⁶⁹)-(2²)¹⁷:2³³+35}=
   3+2*[(2⁵⁴*3⁷⁰):(2⁵¹*3⁶⁹)-2³⁴:2³³+35]=
   3+2*[(2⁵⁴:2⁵¹)*(3⁷⁰:3⁶⁹)-2³⁴⁻³³+35]=
   3+2*(2⁵⁴⁻⁵¹*3⁷⁰⁻⁶⁹-2+35)=
   3+2*(2³*3+33)=
   3+2(8*3+33)=
   3+2(24+33)=3+2*57=3+114=117

b)3³+3²⁰:3¹⁸*3+3*3⁸:3⁶+3¹⁰:(8*3⁵+3⁵)-4*3³=
  3³+3²⁰⁻¹⁸⁺¹+3¹⁺⁸⁻⁶+3¹⁰:3⁵(8+1)-2²*3³=
  3³+3³+3³+3¹⁰⁻⁵:9-2²*3³=
  3³+3³+3³+3⁵:3²-2²*3³=
  3³+3³+3³+3³-2²*3³=
  3³(1+1+1+1-2²)=
  3³(4-4)=
  3³*0= 0

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