Question

Sa se calculeze: a) (3+2x) (3-2x)+5x(x-4)-2x=  b) -4(x+1)+2x=  c) (2x+1)²-(2x-1)²=  d) (x+8) (x-2)+(x+2) (x-8).Rezolvari complete.

Answer 1

a)(3+2x) (3-2x)+5x(x-4)-2x=

9-6x+6x-4$x^{2}$+5$x^{2}$-20x-2x=
=9-22x+$x^{2}$
b)-4(x+1)+2x=
=-4x-4+2x=
=-2x-4
c)(2x+1)²-(2x-1)²=
=4$x^{2}$+1-4$x^{2}$-1=
=0
d)(x+8)(x-2)+(x+2)(x-8)=
=$x^{2}$-2x+8x-16+$x^{2}$-8x+2x-16=
=x la puterea 4 -32