Question

Să se calculeze a) 3/4+1/3-(1-1/2) b) 5/6+1/2-(1/2-1/3) c) 15/16-1/2-(7/8-3/4)d)4-1/8-[2-(3/2-3:4)]e)13/20+1/2-(1/4+1/5)​

Answer 1

Răspuns:

Explicație pas cu pas:

-  ADUC LA ACELASI NUMITOR (valabil pentru toate punctele

a) = (9+4)/12 - [(2-1)/2] = 13/12 - 1/2 =(13 - 6)/12 = 7/12

b) = (5+3)/6 - [(3 -2)/6] = 8/6 - 1/6 = 7/6

c) = (15-8)/16 - [(7-6)/8] = 7/16 - 1/8 = (7-2)/16 = 5/16

d) = (32-1)/8 - [2-(6-3)/4] = 31/8-[2 -3/4] = 31/8 -(8-3)/4 = 31/8 -5/4 =(31-10)/8 =21/8

e) = (13 + 10)/20 - (5 + 4)/20 =23/20 - 9/20 = 14/20 = 7/10