Question

Sa se calculeze:
A)$\sqrt[3]{27^2} =$
$\sqrt[3]{-64} =$
$\sqrt[3]{-343} =$
$\sqrt[3]{ \sqrt{729} } =$
B) $\sqrt{ \frac{36}{49} } =$
 $\sqrt[3]{- \frac{216}{125} } =$
$\sqrt[3]{512 ^{-1} } =$
$\sqrt[3]{-0,008} =$

Answer 1

La radicalii de ordin impar minusul de sub radica iese in fata.