Question

Sa se calculeze căldură molara izocora a unui amestec de gaze având exponentul adiabatic 1,5.

Answer 1

[tex]\displaystyle \text{Se da:}\\ \\ \gamma=1,5\\ \\ C_v=?\\ \\ \\ \text{Formule:}\\ \\ \text{Formula coeficientului adiabatic:}\\ \\ \\ \gamma=\frac{C_p}{C_v}\\ \\ \\ \text{Din relatia lui Mayer avem:}\\ \\ \\ [/tex]


$\displaystyle C_p-C_v=R\Rightarrow C_p=C_v+R,\text{ deci:}\\ \\ \\ \gamma=\frac{C_v+R}{C_v}\\ \\ \gamma\times C_v=C_v+R\\ \\ \gamma\times C_v-C_v=R\\ \\ C_v\times(\gamma-1)=R\\ \\ \\ \boxed{C_v=\frac{R}{\gamma-1}}\\ \\ \\ \text{Calcule:}\\ \\ C_v=\frac{8,31}{1,5}\approx 5,54$