Question

Sa se calculeze ce volum ocupa o masa de O2 de 1kg.Cate molecule se gasesc in 10kg H2O

Answer 1

MO2=32kg/kmol

m=1kg

n=m/M=1/32=0,03125 kmoli

n=V/Vm=>V=n*Vm=0,03125*22,4=0,7m³ O2 = 700L

MH2O=18kg/kmol

n=m/M=10/18=0,5(5) kmoli H2O = 555,555 moli H2O

1 mol H2O...............................NA=6,022*10^23 molecule
555,555 moli..........................x=3345,5(5)*10^23 molecule = 33,45(5)*10^25 molecule H2O

Answer 2

V = nr moli * 22,4 = m/masa molara O2 
V = [1000/(2*16)]*22,4 = 700 l oxigen

1 mol substanta contine 6,022* 10^23 molecule (1 mol apa = 18 g)

18 g H2O...................6,022 * 10^23 molecule apa
10000 g..................,,,x molecule apa
x = 33,45 * 10^25 molecule apa