Question

Sa se calculeze concentratia procentuala obtinuta prin amestecarea a 250g KOH 15 la suta cu 500 g KOH10 la suta si 150 g apa

Answer 1

ms1=250 g

c1=15%

ms2=500 g

c2=10%

mH2O=150 g

cfinal=?

md1=15*250/100=37,5g

md2=10*500/100=50 g

mdfinal=md1+md2=37,5+50=87,5 g

msf=ms1+ms2+mH2O=250+500+150 =900 g

c finam=mdf/msf*100=9,72 %