Question

sa se calculeze coordonatele vârfului parabole xla puterea a doua+2x-3​

Answer 1

x²+2x-3=0

V(xV; yV)

xV=-b/(2a)=-2/2=-1

yV=-Δ/(4a)=-(4+12)/4=-16/4=-4

=> V(-1; -4)

Answer 2

f(x) = x²+2x-3

Avem V(-b/2a, f(-b/2a))

-b/2a = -2/2 = -1

=> f(-1) = (-1)²-2-3 = 1-2-3 = -4

=> V(-1, -4)