Question

sa se calculeze integrala definita
1
∫(x²-8³√x)dx
-1

Answer 1

2/3 mia, trebuie de separat in 2 integrale apoi e usor

Answer 2

$\int\limits^1_ {-1} (x^2-8 \sqrt[3]{x} \,) dx= ( \frac{x^3}{3}-8 *\frac{3}{4}*x \sqrt[3]{x})= \frac{1}{3}-6+ \frac{1}{3}+6 = \frac{2}{3}$