Question

Sa se calculeze limita urmatorului sir : [tex]\lim\limits_{n\to+\infty} a_n,\unde\a_n=2^{-n}+n^{-2}[\tex]​

Answer 1

Răspuns:

$\lim\limits_{n\to+\infty} a_n,\\a_n=2^{-n}+n^{-2}\\a_n=\frac{1}{2^{n}} + \frac{1}{n^{2}} \\ \lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{1}{2^{n}} + \lim_{n \to \infty} \frac{1}{n^{2}} = 0+0 =0$