Question

Sa se calculeze log in baza 6 din 16 in functie de a=log in baza 12 din 27

Answer 1

$log_{12}27=a$
$3 log_{12}3=a$
$\frac{3}{ log_{3}12 }=a$
$\frac{3}{ log_{3}4+ log_{3}3 }=a$
$\frac{3}{1+2 log_{3}2 }=a$
$log_{3}2= \frac{3-a}{a}$
$log_{2}3= \frac{a}{3-a}$
$log_{6}16=4 log_{6}2= \frac{4}{ log_{2}6 }= \frac{4}{1+ log_{2}3 }= \frac{4}{1+ \frac{a}{3-a} } = \frac{12-4a}{3}$