Question

Sa se calculeze log₂4+(1/2)la puterea -1 -∛8
Ajutorrr nu am facut asa ceva niciodata si nu stiu cum se rezolva

Answer 1

log₂4+(1/2)la puterea -1 -∛8 ==> log₂4+(1/2)la puterea -1 -∛2³ ==>log₂4+(1/2)la puterea -1 -2 ==>log₂4+2-2==>log₂4==>log₂2²=2

Answer 2

$\log_{2}{2^{2}}+(2^{-1})^{-1}-{2^{3}}^{\frac{1}{3}}=2\log_{2}{2}+2^{-1*(-1)}-2^{3*\frac{1}{3}}=2+2^{1}-2^{1}=2+2-2=2$