Question

sa se calculeze lungimea segmentului ab determinat de punctele a (2 ,-1) si b( 3,5) IN REPERUL CARTEZIAN OXY.

Answer 1

Salut!

Distanta AB = $\sqrt{(3-2)^2+(5-(-1))^2} = \sqrt{1^2 + 6^2} = \sqrt{1 + 36} = \sqrt{37}$

Rezultat: $\sqrt{37}$

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Formula distantei a doua puncte in reperul cartezian xOy:

• $\sqrt{(x_{2}-x_{1})^2 + (y_{2}- y_{1})^2 }$

Succes!