Question

Sa se calculeze media aritmetica si media geometrica a numerelor:

x=[tex]2 \frac{1}{2} + 3 \frac{1}{3} - \frac{5}{6}
[/tex]

y=[tex]15 \frac{1}{4} + 6 \frac{1}{9} - 1 \frac{13}{36}
[/tex]

Answer 1

$x= \frac{5}{2}+ \frac{10}{3}- \frac{5}{6}= \frac{15+20-5}{6}=5 \\ y= \frac{61}{4}+ \frac{55}{9}- \frac{49}{36}= \frac{549+220-49}{36}=20 \\ m_{a}= \frac{5+20}{2}=12,5 \\ m_{g}= \sqrt{5*20}=10$