Question

Sa se calculeze nr de moli din: 269 g clorura de fier

733 g clorura de natriu

777 g clorura de calciu

1700 kg acid sulfhidric

270 g oxid de azot

455 g clorura de cupru
Dau coroana, e urgent!!!!!!!!!!!!!

Answer 1

Răspuns:

Explicație:

nr. de moli = n

n = m : M -------->    m =masa subst. [ g ]  ; M =masa molara [g/moli  ]

MFeCl3=56 + 3.35,5=162,5--------> 162,5g/moli

n =269 g : 162,5g/moli=1,65 moli FeCl3

[daca este FeCl2-------> M =56+ 71=127

n=269g : 127g/moli=2,11 moli FeCl2   ]

MNaCl=23 +35,5=58,5 ------> 58,5g/moli

n=733g : 58,5g/moli=12,52 moli NaCl

MCaCl2=40+71=111------->111 g/moli

n=777g : 111 g/moli=7 moli CaCl2

MH2S=2 +32 =34-------->34g/moli

n=1700g : 34g/moli=50 moli H2S

MNO=14 +16=30------->30g/moli

n=270g : 30g/moli=9 moli NO

MCuCl2=64 +71=135 -------->135g/moli

n=455 g : 135g/moli=3,37 moli CuCl2