Question

Sa se calculeze numerele reale a,b,c stiid ca: a²+b²-4a+10b+29=0

Answer 1

$a^{2}+ b^{2} -4a+10b+29= a^{2} -4a+4+ b^{2} +10b+25=$
$(a-2)^{2} + (b+5)^{2} =0=>a=2, b=-5$