Question

sa se calculeze primii 5 termeni ai progresiei

$x_{n} = \frac{3n-2}{n+2}$

Va rog mult

Answer 1

x₀=$\frac{3*0-2}{0+2}$=-1
x₁=$\frac{3*1-2}{1+2}$=$\frac{1}{3}$
x₂=$\frac{3*2-2}{2+2}$=1
x₃=$\frac{3*3-2}{3+2}$=$\frac{7}{5}$
x₄=$\frac{3*4-2}{4+2}$=$\frac{10}{6}$
x₅=$\frac{3*5-2}{5+2}$=$\frac{13}{7}$