Question

Sa se calculeze $\frac{lg(3+2 \sqrt{2} }{lg( \sqrt{2} +1)}$

Answer 1

$\frac{lg(3+2 \sqrt{2}) }{lg(1+ \sqrt{2}) }= \frac{lg(1+ \sqrt{2} )^2}{lg(1+ \sqrt{2}) } = \frac{2lg(1+ \sqrt{2}) }{lg(1+ \sqrt{2}) }=2$