Question

Sa se calculeze$\int\limits^1_0f( {x}) \, dx$ f(x)=1/x+2

Answer 1

$\int_{0}^{1}\frac{1}{x+2}dx=ln(x+2)|_{0}^{1}=ln(1+2)-ln(0+2)=ln3-ln2=ln\frac{3}{2}$