Question

Să se dea:
1)(3+ radical 5)-(4+radical 5)+8=
2)7+radical 2-(radical 2-3)=
3)|1- radical 3|+2- radical 3=​

Answer 1

Răspuns:

$1) (3 + \sqrt{5} ) - (4 + \sqrt{5} ) + 8 = \\ 3 \times 4 + 3 \times \sqrt{5} - \sqrt{5} \times 4 + \sqrt{5} \times \sqrt{5} + 8 = \\ 12 + 3 \sqrt{5} - 4 \sqrt{5} + \sqrt{25} + 8 = \\ 12 - \sqrt{5} + 5 + 8 = \\ \sqrt{5} + 25$

$2)7 + \sqrt{2} - ( \sqrt{2} - 3) = \\ 7 + \sqrt{2} \times \sqrt{2} - \sqrt{2} \times 3 = \\ 7 + \sqrt{4} - 3 \sqrt{2} = \\ 7 + 2 - 3 \sqrt{2} = 9 - 3 \sqrt{2}$

$3) |1 - \sqrt{3} | + 2 \sqrt{3} = \\ 1 + \sqrt{3} + 2 - \sqrt{3} = 3$

Explicație pas cu pas:

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