Question

sa se determine 4 numere naturale care indeplinesc conditiile:a)suma lor este 160 b)adunand la primul numar 3 ,scazand din al doilea 3,inmultinda al treilea numar cu 3 ,si impartind al 4 nr la 3 toate nr for fi egale

Answer 1

a+b+c+d=160
a+3=b-3=3c=d/3
b=a+6
c=(a+3)/3
d=3(a+3)
a+a+6+(a+3)/3+3(a+3)=160
2a+(a+3)/3+3a+9=160-6
5a+(a+3)/3=154-9
5a+(a+3)/3=145
15a+a+3=435
16a=432
a=27
b=a+6=27+6=33
c=(a+3)/3=(27+3)/3=10
d=3(a+3)=3(27+3)=90

Answer 2

a+b+c+d=160
a+3=b-3=3c=d/3
b=a+6
c=(a+3)/3
d=3(a+3)
a+a+6+(a+3)/3+3(a+3)=160
2a+(a+3)/3+3a+9=160-6
5a+(a+3)/3=154-9
5a+(a+3)/3=145
15a+a+3=435
16a=432
a=27
b=a+6=27+6=33
c=(a+3)/3=(27+3)/3=10
d=3(a+3)=3(27+3)=90