Question

Sa se determine cel mai mic multiplu al perechilor de numere: (5;9) (12;15) (4;7) (15;20) (30;45) va rog mult urgentt.​

Answer 1

[5; 9] = 45

5 = 5;

9 = 3²

[12; 15] = 60

12 = 2² × 3

15 = 5 × 3

[4; 7] = 28

4 = 2²

7 = 7

[15; 20] = 60

15 = 5 × 3

20 = 2² × 5

[30; 45] = 90

30 = 2 × 5 × 3

45 = 5 × 3²

-Luke48