Question

sa se determine doua nr naturale stiind ca csuma lor este 2013 iar daca se impart cele doua nr se obtine catul 4 si restul 3

Answer 1

a+b=2013

a:b=4 rest 3

a=4b+3

4b+3+b=2013

5b=2013-3

5b=2010

b=402

a=4*402+3

a=1608+3

a=1611

Answer 2

a + b = 2013
a : b = 4 rest 3
a = 4b + 3
a  ___/___/___/___/ + 3
b  ___/
4b + 3 + b = 2013
5b = 2013 - 3
5b = 2010
b = 2010: 5
b = 402
a = 4 * 402 + 3
a = 1608 + 3
a = 1611