Question

SA SE DETERMINE EC DR CARE CONTINE PCT A(2,3) SI B(-3,-2)

Answer 1

Răspuns:

y = x + 1

Explicație pas cu pas:

A(2, 3); B(-3, -2)

$A(x_{A}; y_{A}), B(x_{B}; y_{B})$

$\frac{y - y_{B}}{y_{A} - y_{B}} = \frac{x - x_{B}}{x_{A} - x_{B}} \iff \frac{y - ( - 2)}{3 - ( - 2)} = \frac{x - ( - 3)}{2 - ( - 3)} \\ \frac{y + 2}{5} = \frac{x + 3}{5} \iff y + 2 = x + 3 \\ \bf y = x + 1\iff x - y + 1 = 0$