Question

Sa se determine ecuatia dreptei AB pt:A(3;-2) B(-1;5)

Answer 1

$\frac{y-y_A}{y_b - y_A} = \frac{x - x_A}{x_B - x_A} </p><p>\\Avem A(3,-2) si B(-1,5).$

$\frac{y-(-2)}{5-(-2)} = \frac{x-3}{-1-3}  <=> \frac{y+2}{7} = \frac{x-3}{-4}  <=> -4(y+2)=7(x-3) <=> -4y-8=7x-21 <=> -7x -4y+13=0$