Question

sa se determine fractiile 3/a,4/b,5/c,stiind ca reprezinta acelasi nr rational si ca 2c+3b-4a=40

Answer 1

3/a=k    a=3/k
4/b=k    b=4/k
5/c=k    c=5/k
2c+3b-4a=40
2*5/k+3*4/k-4*3/k=40
10/k+12/k-12/k=40
10/k=40
k=1/4
a=3/(1/4)=3*4=12
b=4/(1/4)=4*4=16
c=5/(1/4)=5*4=20